English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Why would a Frisbee fly on the airless moon?

2007-03-27 16:00:58 · 3 answers · asked by Yarka 1 in Science & Mathematics Physics

3 answers

there really isn't a physics equation that could answer this

but...

its all about gravity and the rate that things fall

when using physics, on "earth" objects fall in a vacuum at a rate of 9.8 meters per second, there is no air or air resistance, so, considere the frisbee flying through a vacuum, all you have to do is substitute the coefficient of gravity, or "A" for acceleration

2007-03-27 16:10:38 · answer #1 · answered by Eric D 3 · 0 0

Think of it this way: On the Earth, when you throw a frisbee, the reason it glides is due to its shape (which generates a lift, similar to the wings of a plane) and its spinning motion (also known as the angular momentum). The angular momentum causes the frisbee to continue flying in a circular motion. However, the frisbee comes to a stop due to the effects of air resistance and gravity. On the moon, the effect of gravity isn't as strong and you don't encounter any air resistance, which is why it would continue to fly.

2007-03-27 23:17:18 · answer #2 · answered by AnonymousOne 2 · 0 0

It would not "fly" the way a Frisbee flies on earth, because it is air that causes the typical Frisbee float. It would "fly" the way a thrown rock would fly.

2007-03-27 23:11:36 · answer #3 · answered by CheeseHead 2 · 0 0

fedest.com, questions and answers