factor
m3 - 7m2 - 78m
(the 3 = cubed and the 2= squared)
solve for x
x2+5x= -6
(the 2 is x squared)
2007-03-27 15:55:43 · 4 answers · asked by lemonzap44 1 in Education & Reference ➔ Homework Help
m^3 - 7m^2 - 78m
= m (m^2 - 7m - 78)
= m (m - 13) (m + 6)
x^2 + 5x = -6
x^2 + 5x + 6 = 0
(x + 2) (x +3) = 0
then either x + 2 = 0 ; x = -2
or x +3 = 0 , x = -3
so x is either -2 or -3
2007-03-27 16:05:32 · answer #1 · answered by rooster1981 4 · 0⤊ 0⤋
m(m^2 -7m -78)
x^2 + 5x = -6
x^2 + 5x + 6= 0
(x + 2)(x + 3)=0
x+2=0 or x+3=0
so, x=-2 or -3
2007-03-27 23:03:35 · answer #2 · answered by sam b 5 · 0⤊ 0⤋
for the second one::
x2+5x=-6
x2+5x+6=0
(x+2)(x+3)
x=-2 x=-3
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for the first one::
first divide all of the numbers by "m"
so...
m(m2-7m-78)
m(m - 13)(m + 6)
2007-03-27 23:06:05 · answer #3 · answered by ♥•Softball•Chick•♥ 4 · 0⤊ 0⤋
the first one is
m(m2-7m-78)= m(m+13)(m-6)
2007-03-27 23:05:23 · answer #4 · answered by balla15 2 · 0⤊ 0⤋