factor
2(a+b) + 3(a+b)
2007-03-27 15:46:19 · 9 answers · asked by lemonzap44 1 in Education & Reference ➔ Homework Help
2a + 2b +3a+3b= 5a+5b
5a+5b
2007-03-27 15:51:11 · answer #1 · answered by dfatgut 2 · 0⤊ 0⤋
2(a+b) + 3(a+b)
=2a+2b+3a+3b
because 2(a+b) is equal to 2a+2b cos you would need to multiple the 2 to both the pronumerals in the bracket. Same as 3(a+b)
then you would symplify it
=5a+5b
note: you can only add the ones with the same pronumeral value
2007-03-29 07:20:57 · answer #2 · answered by Kyki 2 · 0⤊ 0⤋
2(a+b) + 3(a+b)
= 2a + 2b + 3a + 3b
= 2a + 3a + 2b + 3b
= 5a + 5b
= 5(a + b)
2007-03-27 22:55:13 · answer #3 · answered by jinu j 1 · 0⤊ 0⤋
take out a+b
(a+b) (2+3)
5(a+b)
2007-03-27 22:56:58 · answer #4 · answered by 7 · 0⤊ 0⤋
5(a+b)
2007-03-27 22:49:39 · answer #5 · answered by Chump 1 · 1⤊ 0⤋
2a+2b + 3a +3b =
5a+5b
Answer= 5a+5b
and yout not really factoring your distributing
2007-03-27 22:51:12 · answer #6 · answered by javi01 2 · 0⤊ 0⤋
Distribute..
2a+2b+3a+3b
Combine like terms:
5a+5b
And there you go
2007-03-27 22:51:24 · answer #7 · answered by Anonymous · 0⤊ 0⤋
2a+2b+3a+3b=
5a+5b=
5(a+b)
2007-03-27 23:34:01 · answer #8 · answered by EllieDracula 2 · 0⤊ 0⤋
2a+2b+3a+3b=(Anwer 5a+5b)
2007-03-27 22:57:25 · answer #9 · answered by thethe59 1 · 0⤊ 0⤋