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Hello guys, I really need help with this physics problem. It has been bugging me for a while and I keep getting stuck. If you can't solve it, if you know where I can find a site that has solutions this would be a great help. Thanks!

A l.0 kilogram object is moving horizontally with a velocity of 10 meters per second, as shown above, when it makes a glancing collision with the lower end of a bar that was hanging vertically at rest before the collision. For the system consisting of the object and bar, linear momentum is not conserved in this collision, but kinetic energy is conserved. The bar, which has a length l of 1.2 meters and a mass m of 3.0 kilograms, is pivoted about the upper end. Immediately after the collision the object moves with speed v at an angle  relative to its original direction. The bar swings freely, and after the collision reaches a maximum angle of 90° to the vertical. The moment of inertia of the bar about the pivot is Ibar = ml²/3 Ignore friction.

2007-03-27 14:59:32 · 2 answers · asked by djibouti1989 1 in Science & Mathematics Physics

a. Determine the angular velocity of the bar immediately after the collision.

b. Determine the speed v of the l kilogram object immediately after the collision.

c. Determine the magnitude of the angular momentum of the object about the pivot just before the collision.

d. Determine the angle .

2007-03-27 15:00:29 · update #1

2 answers

u'll have 2 give the figure of d prob

2007-03-27 19:22:25 · answer #1 · answered by joe j 2 · 0 0

only way to do this would be to show the above.

2007-03-27 15:15:13 · answer #2 · answered by climberguy12 7 · 0 0

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