Balance the following equation by the half-reaction method in an acidic or basic solution as indicated.?

Question

Balance the following equation by the half-reaction method in an acidic or basic solution as indicated.


I - + NO2- --> I2 + NO ( acidic )


You must enter the correct coefficients of the above reactants and products as a single group of integers.


Example:

C2H5OH(aq) + Cr2O72-(aq) --> CH3CO2H(aq) + Cr3+(aq)



the balanced equation is

3C2H5OH(aq) + 2Cr2O72-(aq) + 16H3O+(aq) --> 3CH3CO2H(aq) + 4Cr3+(aq) + 27H2O(l)



you would enter 3234 for an answer.

NOTE: only enter the coefficients for the species given in the original equation.


please help, Im really lost with this one

Thanks

Answer 1

2I- >> I2 +2e-
(NO2- +2H + +1e->> NO+ H2O)2
2NO2- +4H+ +2e- >> 2NO+2H2O


2I- + 2NO2- +4H+ >> I2 + 2NO +2H2O

Answer 2

in accordance to I-+NO2 ? I2 + NO, the products section contain 2 Iodine molecules (I2 because of very fact its a gas) and on the reactant section there exists 2 NO molecules. shall we want to stability in this party. I(2)-+NO2?I2+NO(2) so.. 2112