How does that velocity compare with the escape velocity from the sun? describe how your results help account for the fact that red giants have strong stellar winds!??? PLEASE HELP I NEED THE ANSWER IN 5 MINUTES!!!
2007-03-27 12:24:19 · 2 answers · asked by Audiologic Apparel 1 in Science & Mathematics ➔ Astronomy & Space
Well, I guess this is too late, but you need the equation for escape velocity:
v^2 = 2GM/R
Escape velocity goes as the inverse square root of the radius. So for something 100 times larger than the Sun but the same mass as the Sun, the escape velocity would be 10 times smaller. A lower escape velocity means more material can escape (obviously).
2007-03-27 12:44:06 · answer #1 · answered by kris 6 · 1⤊ 0⤋
Gravitational acceleration, a = GM / r^2. the place G is the gravitational consistent; M is the mass, and r is the radius. a is proportional to mass and is inversely proportional to the sq. of the radius. The get away speed is proportional to gravitational acceleration and to gravitational rigidity. The pink huge has a mass of a million mega-suns and a radius of a hundred and forty image voltaic radii. The pink huge has a gravitational acceleration, from a factor at its center, of a million million circumstances that of the sunlight (from the a reference factor of the middle of the sunlight). The gravitational acceleration, and subsequently the get away speed of the pink huge, at it particularly is floor is a million / (a hundred and forty^2) that of the sunlight at an equivalent mass. as a result, the pink huge has an get away speed, v = 10^6 / a hundred and forty^2 = fifty one.02 circumstances that of the sunlight.
2016-10-20 02:21:18 · answer #2 · answered by Anonymous · 0⤊ 0⤋