English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

If a proton travels between two oppositely charged plates (that start from rest). And the proton hits the negative plate at a speed of 3.8 x 104 m/s. How would you find the potential difference between the plates?

2007-03-27 12:09:55 · 3 answers · asked by Question-er 2 in Science & Mathematics Physics

3 answers

The potential between the plates times the charge on the proton is equal to the kinetic energy gained by the proton. Therefore

.5*m*v^2 = V*q, or V = .5*m*v^2 / q

m = proton mass
q = proton charge
v = change in proton velocity

2007-03-27 12:19:48 · answer #1 · answered by gp4rts 7 · 0 0

Draw a real angled triangle. tension electric powered = Fel to the ideal (say) = E q = V q /d tension weight rapidly down = mg draw in the hypoteneuse to represent the stress T perspective of string to horizontal = seventy six deg tan seventy six = mg/Fel = m g d / Vq so V = m g d / ( q x tan76) = 377 Volts With 3 forces in equilibrium, triangles continually seems the least perplexing thank you to bypass, exceptionally if there's a ninety degree triangle.

2016-12-08 12:47:39 · answer #2 · answered by ? 4 · 0 0

challenging problem. search with a search engine. it can help!

2014-10-31 21:13:33 · answer #3 · answered by Anonymous · 0 0

fedest.com, questions and answers