If one mole of H2SO4 and 2 moles of NaOH react, full neutralization takes place. So the 2 OH- join with 2H+?

Question

to form 2 mols of H2o. The normality of H2so4 or NaOH in this case is 2.

Now if I'm getting an acid salt(NaHSO4) what will be the normality?

Answer 1

Normality and Molarity are related through the equation

N=aM where a is the number of equivalnts in the molecular formula.

For H2SO4, you have 2 H+ in the molecular formula, thus a=2, N=2*M and N=2 only when M=1. So you can't say that normality is 2 just because 1 mole of H2SO4 reacted; you would say it only if 1 mole/L reacted.

For NaHSO4 you can sse that there is 1 H+ in the molecular formula, thus a=1 and N=M.

You should also be careful how you use normality: for acid-base reactions it is the number of H+/OH-, for redox it is the number of e, for ion exchange the number of charges etc. So sometimes (though not usually) a certain solution could have different normality depending on the reaction you are referring to.

Such a case is nitric acid
What's the normality of 1M HNO3?
As an acid, it has 1H+ in the molecular formula, thus a=1 and N=1*M=M=1
As an oxidizing agent it can be reduced to either NO2 or NO, depending on the conditions. In the first case it changes oxidation number from +5 to +4, thus it takes 1 e, thus a=1 and again N=M=1 but in the second case the change is from +5 to +2 thus it takes 3 e, a=3 and N=3*M= 3