Two particles, with identical positive charges and a separation of 2.00 * 10^ (-2) m, are released from rest. Immediately after the release, particle 1 has an accleration a1 whose magnitude is 4.600 * 10^3 m/s ^2, while particle 2 has an acceleration a2 whose magnitude is 8.50 * 10^3 m/s^2. Particle 1 has a mass of 6.00*10^-6 kg.
a) Find the charge on each particle:
b) Find the mass of particle 2:
2007-03-27 04:41:04 · 2 answers · asked by Alan l 1 in Science & Mathematics ➔ Physics
Ok, let's remember the Coulomb's law :
Fe = K*q1*q2 / r^2
r = distance
q1 and q2 = charges
K = constant
Using the Newton's second law :
Fe = m1*a1
Fe = 6*10^-6*4.6*10^3
Fe = K*q*q / (2*10^-2)^2
K = 9*10^9
9*10^9*q^2 / 4*10^-4 = 27.6*10^-3
q^2 = 12.2*10^-16
q = 3.5*10^-8 Coulombs
To find the mass of particle 2 :
Fe = m2*a2
9*10^9*(3.5*10^-8)^2 / 4*10^-4 = m2*8.5*10^3
27.6*10^-3 = m2*8.5*10^3
m2 = 3.25*10^6 kg
Hope that helped you
2007-03-27 04:48:44 · answer #1 · answered by anakin_louix 6 · 0⤊ 0⤋
Good luck with this one my friend. Sorry I couldn't help.
2007-03-27 04:50:09 · answer #2 · answered by Psycho Chicken! 5 · 0⤊ 0⤋