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A charge of +q is located at the origin, while an identical charge is located on the x axis at x= 0.55 m. A third charge of +5 q is located on the x axis at such a place that the net electrostatic force on the charge at the origin triples, its direction remain unchanged. Where should the third charge be located?

2007-03-27 04:37:27 · 2 answers · asked by Alan l 1 in Science & Mathematics Physics

2 answers

Ok, here you have to remeber the electric force for point charges :

Fe = K*q1*q2 / d^2

d = distance

q1 and q2 = charges

K = electrostatic constant

Force on the charge at the origin by the second charge :

K*q*q / (0.55)^2 = Fe

If you put another charge, and the electric force triples :

3Fe = k*q*q / (0.55)^2 + k*5q*q / r^2

3K*q*q / (0.55)^2 - k*q*q / (0.55)^2 = k*5q*q / r^2

2kq^2 / 0.55^2 = k5q^2 / r^2

r^2 = 5*(0.55)^2 / 2

r = 0.87

The charge should be located at x = 0.87

2007-03-27 04:43:56 · answer #1 · answered by anakin_louix 6 · 0 0

HE'S AN INVADER???!!!

2007-03-27 11:40:52 · answer #2 · answered by Shady Hazem 2 · 0 0

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