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A human hair breaks under a tension force of 1.2 N. If the tensile strength of human hair is about 2.0x108 Pa, what is the diameter of the hair in microns (10-6m)?

2007-03-27 02:56:39 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

Ok, just remember :

Tensile strenght = Force / Surface :

2*10^8 = 1.2 / Surface

Surface = 0.6*10^-8 m^2

But, if we consider that, as the surface of a circle :

0.6*10^-8 = pi*r^2

r = sqrt(0.2*10^-8) = 0.4*10^-4

diameter = 2r = 0.8*10^-4

In microns : 80 uM >>> microns

2007-03-27 04:14:21 · answer #1 · answered by anakin_louix 6 · 0 0

6*10^-9 meters

1.2 / (2.0*10^8) = 6*10^-9 meters


---Wait, that's the area of the hair, not the diameter.

2007-03-27 10:01:32 · answer #2 · answered by Anonymous · 0 0

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