a proton moved 10 cm along the direction of an electric field of strength 3.0 N/C. The electric potential?

Question

difference between the protons initial and ending point is___. (proton charge=+1.6x10^-19 C)

Answer 1

The equation that relates electric potential to field is:
Ed = V
V = (3.0)(10/100)
The difference, or deltaV, is V you got in above equation.