2007-03-27 01:20:35 · 8 answers · asked by "A!" 1 in Science & Mathematics ➔ Mathematics
- + - = +
- + + = -
+ + + = +
It's plus......
2007-03-27 01:28:25 · answer #1 · answered by Lee.Na 5 · 0⤊ 0⤋
Let the two integers be X and Y, where X > 0 > Y.
Since Y < 0, -Y > 0 (the negative of a negative number is positive). Consequently, since addition of two positive numbers yield a positive number, we get:
X - Y > 0, which implies X > Y.
This last inequality says that the positive integer X is greater than the negative integer Y.
Of course, if we were to place the context of "order" (i.e. greater than, less than) in terms of absolute values (e.g. ABS(1) = ABS(-1) = 1), then that would be a different matter altogether.
2007-03-27 08:28:24 · answer #2 · answered by JoseABDris 2 · 0⤊ 0⤋
Algebraically, the integer with +ve sign is greater than the greatest integer with -ve sign. In fact, even zero is greater than a negative number. Numbers to the right side of a given numbers are greater and numbers to the left side are smaller in a number line.
If we take modulus value, we are of course ignoring the negative sign and then the numerical value alone is important.
2007-03-27 08:47:13 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋
The one with the + sign
2007-03-27 08:31:05 · answer #4 · answered by durriyaa 2 · 0⤊ 0⤋
the integer with + sign is greater
2007-03-27 08:24:09 · answer #5 · answered by pinky 2 · 0⤊ 0⤋
The one with a positive sign.
2007-03-27 08:30:05 · answer #6 · answered by roy v 1 · 0⤊ 0⤋
the one with + sign
2007-03-27 08:23:03 · answer #7 · answered by sam 2 · 0⤊ 0⤋
You're kidding, right? You did say integer, not variable, right?
The positive one (unless this is a trick question)
2007-03-27 08:24:05 · answer #8 · answered by blighmaster 3 · 0⤊ 0⤋