the possible answer is in a/b form
2007-03-26 23:41:04 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
As in the denominator power is common therefore it can be shown as :
= 1/( (2+3+6)^13)
=1/(11^1/3);
= 1/2.25 (Approx.);
2007-03-27 00:04:36 · answer #1 · answered by sb 7 · 0⤊ 2⤋
Well, suppose each is a, b, c
a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca)
Using this we can find out (a+b+c)
= [ 2^(2/3) + 3^(2/3) + 6^(2/3) - 6^(1/3) - 12^(1/3) - 18^(1/3) ] / [11 - 3(36)^1/3]
Try to simplify it further.
2007-03-27 06:58:51 · answer #2 · answered by nayanmange 4 · 0⤊ 0⤋
the ans is 3/11..wots so difficult in this qustuion)))
1/(2^1/3+3^1/3+6^1/3)
1/(2/3+3/3+6/3)
1/(11/3)
3/11
2007-03-27 07:06:15 · answer #3 · answered by Anonymous · 0⤊ 2⤋
1/(11)^1/3 or 1/Cube Root of 11
2007-03-27 06:54:18 · answer #4 · answered by Curtis H 2 · 0⤊ 2⤋
answer by calculating is 0.221273636
2007-03-27 06:57:26 · answer #5 · answered by Soham 1 · 0⤊ 0⤋