Which one of you super intelligent people can answer this? Need real answers too and no play answers.?

Question

Who can give me the answer to the questions below? or where can i get online math help to answer these questions:

1) Using the quadratic equation x2 - 6x + 8 = 0, perform the following tasks:
a) Solve by factoring.
Answer:
Show work in this space.







b) Solve by using the quadratic formula. >>x2 - 6x + 8 = 0,
Answer:
Show work in this space.




2) For the function y = x2 - 6x + 8, perform the following tasks:
a) Put the function in the form y = a(x - h)2 + k.
Answer:
Show work in this space.



b) What is the equation for the line of symmetry for the graph of this function?
Answer:




c) Graph the function using the equation in part a. Explain why it is not necessary to plot points to graph when using y = a (x - h) 2 + k.
Show graph here.


Explanation of graphing.


d) In your own words, describe how this graph compares to the graph of y = x2?
Answer:




3) Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t. This function is s = -16t2 + v0t + s0
• 16 represents ½g, the gravitational pull due to gravity (measured in feet per second 2).
• v0 is the initial velocity (how hard do you throw the object, measured in feet per second).
• s0 is the initial distance above ground (in feet). If you are standing on the ground, then s0 = 0.
a) What is the function that describes this problem?
Answer:




b) The ball will be how high above the ground after 1 second?
Answer:
Show work in this space.




c) How long will it take to hit the ground?
Answer:
Show work in this space.




d) What is the maximum height of the ball?
Answer:
Show work in this space.



4) Amanda has 400 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). She wants to maximize the area of her patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation. Use the vertex form to find the maximum area.

Answer:
Show work in this space.

Answer 1

Look, you really should try to do some of your work yourself. It really is the best way to learn.

Nevertheless:
1) a) x^2 - 6x + 8 = 0
<=> (x - 4) (x - 2) = 0
<=> x = 2 or 4.

b) x = [-(-6) ± √((-6)^2 - 4(1)(8))] / 2
= (6 ± √ (36 - 32)) / 2
= 3 & pm; 2/2
= 2 or 4.

2) a) y = x^2 - 6x + 8
= (x^2 - 6x + 9) - 1
= (x - 3)^2 - 1.

b) x = 3

c) I won't graph it here, you should be able to do that easily enough. You can tell where all the major features are directly from the equation in the form y = a (x - h) 2 + k, so you don't need to plot points. E.g. minimum is at (3, -1), and you've found the x-intercepts in (1).

d) Shifted three units to the right and one down.


3) a) This is just substituting the given values:
s = -16t^2 + 32t + 0 = 32t - 16t^2.

b) s(1) = 32(1) - 16(1)^2 = 16 feet.

c) To hit the ground, we want s(t) = 0, so 32t = 16t^2 => t = 0 or 2. So it hits the ground again after 2 seconds.

d) We know the maximum will be at t = -b/2a = -32/-32 = 1 second; so the maximum height is s(1) = 16 feet.


4) Let the width be x and the length l, then we have 400 = 2x + 2l so l = 200 - x. The area is A = lx = (200-x)x = 200x - x^2. This is a quadratic equation, and the coefficient of x^2 is negative, so we know there will be a maximum at x = -200 / -2 = 100 feet. Then l = 200 - x = 100 feet also. So the area is 100×100 = 10,000 square feet.
We can derive this directly from the vertex form of the equation, as requested:
A = 200x - x^2 = -(x^2 - 200x)
= -(x^2 - 200x + 100^2) + 100^2
= -(x-100)^2 + 10,000
So the maximum area is 10,000 square feet, as before.

Answer 2

1)a)
x^2 - 6x + 8=0
x^2 - 6x + 9 - 1=0
(x-3)^2 - 1=0
(x-3)^2 = 1
=> (x-3)=1 => x=4
or
=> (x-3)= -1 => x=2


1)b)
x^2 - 6x +8 =0
delta= 6^2 - 4*1*8 = 36 - 32 = 4

x= -b + (delta^1/2) / 2a = 6+2 / 2 = 8/2 = 4
or
x= -b - (delta^1/2) / 2a = 6 - 2 / 2 = 2

2)a)
y= x^2 - 6x + 8
y= x^2 - 6x + 9 - 1
y = (x-3)^2 - 1

b) sorry I don't know about the graph
c) again sorry...
d) sorry :)

3)a) well, the function is exactly what you have mentioned:
y= -16t2 + v0t + s0
but the initial volecity should be united bu meters per second and I don't know about feet per second.
and the rest of the questions are also united by feet that you can't use them in the formulas.
I hope you americans start to use SI units one day so that I can help you in physics problems :D

Answer 3

you should do your homework, but nevertheless: i'll help you on the first question:

1. take the factors of 8 on which if you add or subtract them will give you 6, hence: 4 and 2: hence, (x-4)(x-2) is the factor; setting the equation to zero, x=4, or x=2

Answer 4

dude! ur maths is so hard lol!!!! but seriously dont get other people to do you're homework for you -.-