Given this information, can u help me figure out the moles of sodium bicarbonate and the molar mass of product

Question

Mass of Evaporating dish: 40.92 grams
Mass of evaporating dish + Sodium Bicarbonate: 43.94 grams
Mass of Sodium Bicarbonate: 3.02 grams
Molar Mass of Sodium Bicarbonate: 84.01 grams
Moles of Sodium Bicarbonate:
Mass of evaporating dish + product: 42.87 grams
Mass of product: 1.95 grams
Molar Mass of Product:
Moles of Product:

Answer 1

Moles of Sodium Bicarbonate can be found by dividing the mass of NaHCO3 by its molar mass:
3.02 grams NaHCO3 / 84.01 g/mol = 0.0359 moles

Since you didn't state that you added anything to get a reaction, I'm guessing that you're describing the dehydration and evaporation of sodium bicarbonate, as expressed by the reaction:
2NaHCO3 → Na2CO3 + H2O + CO2

At high temperatures, this occurs quickly, and the H2O boils off, leaving only Na2CO3.

For every 2 moles of NaHCO3 that you start with, you're left with 1 mole of Na2CO3.

Molar mass of product: 2 * Na (23.99) + C (12.01) + 3 *O (16) = 107.99 g/mol

Moles of product = mass / molar mass = 1/2 moles of NaHCO3
Moles = 1.95 g / 107.99 g/mol = 0.0181, which is as expected (almost exactly half of the # of moles of NaHCO3).