The hang time of a basketball player who jumps a vertial distance of 2 feet (0.6 m) is about 0.67 s. What will be the ahng time if the player reaches the same height while jumping 4 feet (1.2 m horizontally)?
2007-03-26 17:44:34 · 2 answers · asked by Tone_Loc 2 in Science & Mathematics ➔ Physics
The “hang time” (the time the jumper is in the air) is solely determined by their initial vertical velocity as they leave the ground.
Assuming the surface that the two jumpers are jumping on is level, then both should both stay in the air for the same amount of time since their maximum height off the ground is the same. Since they both reached the same maximum height, they both had the same initial vertical velocity as they left the ground. The horizontal velocity of the jumpers is irrelevant (perpendicular vectors are independent).
Any horizontal component to the jumper’s total velocity does not contribute to the amount of time they are in the air or how high they get off the ground, assuming that the surface is level.
2007-03-26 17:53:15 · answer #1 · answered by mrjeffy321 7 · 0⤊ 0⤋
The hang time is identical. The length of time that the player remains in the air is a function of the vertical height that the player attains and the downward gravitational force exerted on the body. A force exerted horizontally will not change the length of time that the body remains in the air, though it may appear so to the eye because of the horizontal motion.
2007-03-26 17:54:50 · answer #2 · answered by Marcus75 3 · 0⤊ 0⤋