If i have two photons of light and they have frequencies of 6.00x10^16Hz and the other frequency of 1.20x10^17Hz. If the lower frequency wave (6.00x10^16Hz) has an energy of approximatly 4.00x10^-17J what is the energy of the higher frequency wave (1.20x10^17Hz)?
2007-03-26 17:24:11 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The energy of a photon is directly proportional to its frequency by the equation E=h*v where h=Planck's constant and v=frequency.
Your higher energy photon has frequency 2x that of the lower energy photon. So it will have energy 2x as high as well. Since you figured out the energy of the lower energy photon is 4.00x10^-17J (I'll take your word for it that this is correct), then all you have do is multiple this by 2 to get the energy of the higher energy photon,which is 8x10^-17J.
2007-03-26 18:12:41 · answer #1 · answered by Elisa 4 · 1⤊ 0⤋
Energy and frequency are directly proportional, according to Planck's law
E = h*µ, were h is Planck's constant.
You can get the value of that constant from the first photon's energy and frequency and use it to find the second.
2007-03-26 17:29:17 · answer #2 · answered by gp4rts 7 · 1⤊ 0⤋
The higher frequency/energy wave is twice the frequency of the lower frequency (lower energy wave), so my thinking is that the higher frequency wave has twice the energy of the lower frequency wave:
8x10^-17 j
2007-03-26 17:40:37 · answer #3 · answered by answerING 6 · 1⤊ 0⤋
8.00x10^-17J
2007-03-26 17:35:25 · answer #4 · answered by TfC_137 3 · 1⤊ 0⤋