If the total volume of the gas mixture is 277 mL, what is the mass of Ne in grams?

Question

In a mixture of O2 and Ne gases, the partial pressure of O2 is 0.195 atm. The total pressure is 0.425 atm. The temperature is 38.0oC. If the total volume of the gas mixture is 277 mL, what is the mass of Ne in grams?

Answer 1

P(Ne) = 0.230 atm.

g = PV*MM/RT = 0.230 atm * 0.277 L * 20.2 g/mole / (0.08206 * 311 K)
g = 0.05 g