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Please help me! :)

2007-03-26 13:47:23 · 3 answers · asked by silver 2 in Science & Mathematics Chemistry

3 answers

pOH + pH = 14

pOH = 14 - pH

pOH = 8

[OH-] = antilog (-pOH)

antilog (-8) = 1 x 10^-8

2007-03-26 14:10:59 · answer #1 · answered by mazp66 3 · 0 0

if its a basic solution, con. of [H+] =10 power -8
if its a acidic solution, con. of [H+]= 10 power -6

it depends on the type of solution and the mixture u take.

me a male/17/India.
-car3ik@yahoomail.com

2007-03-26 13:57:45 · answer #2 · answered by karthik kumar 2 · 0 0

[H+] = 10^-pH
[H+] = 10^-6 M

[OH-][H+] = 1x 10^14
[OH-](10^-6) = 1 x 10^-14
[OH-] = 10^-8 M

2007-03-26 13:53:56 · answer #3 · answered by Anonymous · 0 0

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