A hamster jumps onto an exercise wehel for a run. A few seconds later, the hamster is running in place with a?

Question

A hamster jumps onto an exercise wehel for a run. A few seconds later, the hamster is running in place with a speed of 2.2 m/s. Find the work done by the hamster to get the exercise wheel moving, assuming it is a hoop of radius .13m and 6.5g.

Answer 1

Neglecting friction, we know that the work-kinetic energy theorem states that the work done is equal to the change in kinetic energy.

We can assume the hoop is a thin shell, so that it has

I = mR²

KE = ½I ω² + ½m v²

Since ω = v / R

KE = ½ (mR²) v² / R² + ½m v²
KE = mv²


Initially, the hoop is not moving, so KEi = 0

W = KEf - KEi
W = KEf
W = mv²
W = .0065 * 2.2² = 0.03146 J

The hamster does approximately 0.031 J of work.

Answer 2

Hamsters become bored and their favourite endeavor is attempting to flee from their cages. The certainly first-rate hamster cages are glass fish tanks. Get a ten or 15 gallon one from the shop. They are low priced and you do not have got to fear approximately bedding falling out via bars or hammies beginning any doorways. You will even have to purchase a lid. For my 2 hamster cages, I purchased 2 lids at Walmart which can be plastic with monitors. These precise ones have latches so there may be certainly no manner a hamster can push up and get out.

Answer 3

Mr. Booz… assumes that the exercize wheel is a hoop that roles along the ground. I assume it is the type that has an axle so it doesn't have a linear kinetic energy term. If so, you can use Mr. Booz…'s technique -- just delete the 1/2mv^2 part of the 2nd equation and follow through accordingly.

Answer 4

If the hamster does not jump square on the bottom of the wheel, then the work done by the hamster was done by getting onto the wheel.

The force of gravity started the wheel turning when it brought the center of gravity of the wheel closest to the ground.
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