Here is an easy one. If i=square root of(-1), what is i^i?

3 ⤊

2007-03-26 12:20:19 · 3 answers · asked by East Ender 2 in Science & Mathematics ➔ Physics

If we start with the Euler formula

Exp[i θ]=Cos[θ]+i Sin[θ]

So, i=Exp[i π/2]

i^i=Exp[i π/2]^i=Exp[-π/2]

2007-03-26 12:27:15 · answer #1 · answered by 2 meter man 3 · 2⤊ 0⤋

i^i = e^(-pi/2) = 0.207879576

2007-03-26 13:40:35 · answer #2 · answered by catarthur 6 · 0⤊ 0⤋

stop chatting bull ****!!!
i^i is 0.207879576 according to google and all are welcome to check don't know why but why would you want to know OMG!!

2007-03-26 12:36:51 · answer #3 · answered by MN A 1 · 1⤊ 2⤋