What are the fully displayed structures and names of X, E and D(D-CH3COONa+H2O) and the reagent q?

Question

C2H5OH--->(acidified,KMnO4, heat)X-->(q)CH3COONa+H2O
|
|(C2H5OHconc.H2SO4)
E+H2O


The line going down should be from X and the H2SO4 is warm. What are the homologous series to which X and E belong? How would you seperate E from a mixture of X and E?

Answer 1

Me again :) - C2H5OH heated with potassium permanganate forms ethanoic acid as the ultimate oxidation product (that is your X) via the acetaldehyde ethanal.
Structure: CH3-COOH
It's an oxidation reaction with the acidified KMnO4 acting as an oxidising agent.
'q' is dilute sodium hydroxide, which reacts with the ethanoic acid in a simple acid/base reaction producing the sodium salt of the ethanoic acid, and water.
The reaction of X ----> E is a simple esterification as I explained before - X is the ethanoic acid, and adding the ethanol and sulphuric acid catalyses:
CH3-COOH + CH3-CH2-OH --> CH3-COO-CH2CH3 + H2O
So E is your ester, ethyl ethanoate
The homologous series is carboxylic acids and their derivatives, which also includes acid amides and acid anyhydride.
To separate the carboxylic acid and and the ester, you would add water to the test tube, because ethanoic acid and ethanol are both water soluble but ethyl ethanoate is not. You would see a think layer of ester separated out, floating on the surface of the water

Answer 2

i would lightly beat it and to form soft peaks, then skim off any powdery residue, spoon into buttered ramakins and bake for 15mins at 220 degrees, leave to cool and sprinkle with ch300Na

am in awe of you lol

Answer 3

It is Purple