A man and woman carry allele for PKU disease they dont have the disease what is the chance of thier child hav?

Question

a).25 b).50 c) .75 d)1.00

Answer 1

(a)

The alleles are P and p with PP being normal, Pp being carrier and the homozygous autosomal recessive pp being Phenylketonuric (PKU)

Both parents are Pp carriers.

Hence each of them donate a P and a p gene

Their children will have
25% chance of PP
50% chance of Pp
25% chance of pp

Answer 2

Definately answer A. Use a punnett square and assume that the allele for PKU is recessive (pp).
P p
P PP Pp

p Pp pp

The chance that the first generation offspring will have the gene for PKU is 25% .

Answer 3

A 25% LETS SAY THAT THE ALLELE FOR NORMAL IS N AND FOR THE DISESE IS p IF BOTH PARENTS ARE Np AND YOU CROSS THEM THEM YOU GET 25% NN or no disese and 50% Np which would be carriers and 25% pp which would show the symptoms of the disese

Answer 4

It's a 25%(a) chance that they will get it and I believe 75% that they will carry it.

Answer 5

a

if they carry the allele but don't have the disease, it must be recessive aka both carry Aa

Aa x Aa = AA, Aa, Aa, and aa (aa is the only kid that will have the disease)

Answer 6

50 %