Find the next three numbers in each of these sequences:?

Question

-4 -1 2 5 8 11 14 17 20

-1 0 3 8 15 24 35 48 63

-128 -54 -16 -2 0 2 16 54 128

Answer 1

23 (each number is three greater than the previous)

80 (subtract the term from the next one, and you see they increase by two)

For the third one -- I'm not sure. SOmething doesn't seem right. Are you sure about the -54 and 54? Are you sure it isn't -64 and 64? All the other numbers ar epowers of two.

Answer 2

The first sequence is arithmetic - that is, each term is three more than the one before it. Thus the next three terms are 23,26,29.

In the second, look at the differences between adjacent terms. These go: 1,3,5,7, ... , 15. So the next three terms are 63+17 = 80, 80+19=99, and 99+21=120.
80, 99, 120

For the third, divide each term by two:
-64, -27, -8, -1, 0, 1, 8, 27, 64
These are the cubes of -4, -3, -2, ... , 3, 4. So the next terms will be 2*5^3, 2*6^3, 2*7^3.
250, 432, 686.

Answer 3

1) 23, 26, 29. Each number in the sequence is just the last one plus three.

2) The difference between the terms are 1, 3, 5, 7, 9, 11, 13, 15. These are just successive odd numbers. So add 17 to 63 to get 80, then 99, 120.

3) I was getting (-1/2)(4^4), (-2)(3^3), -(2^2)(2^2), but the pattern stopped there. Played around with it more and came up with -2(4^3), -2(3^3), -2(2^3), -2(1^3), etc. Next few terms are 2(125)=250, 2(216)-432, 2(343)=686.

[EDIT: Gah! I just realized Taupin beat me to it. He got a better answer too.]

Answer 4

23 26 29 you add three (3)

78 95 114 you add a consectutive odd number

Sorry, I couldn't get this one

Hope this helped =]

Answer 5

-23, 26, 29
-80, 99, 120
im too lazy to figure out the last one