four moles of carbon monoxide gas occupy a volume of 3.9 liters at a constant temperature and pressure. What volume would 1.75 moles of the gas occupy?
2007-03-26 09:37:13 · 3 answers · asked by Jacquline M 1 in Science & Mathematics ➔ Chemistry
1.75 x 3.9/4
2007-03-26 09:48:28 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋
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2016-05-16 04:53:32 · answer #2 · answered by Anonymous · 0⤊ 0⤋
d = PM/RT d(CO) = (one million.0 atm)*(28 grams/mol)/(0.0821 L*atm/mol*ok)(298 ok) = one million.a hundred and forty four grams/Liter d(NO) = (one million.0 atm)*(30 grams/mol)/(0.0821 L*atm/mol*ok)(298 ok) = one million.226 grams/Liter d(He) = (one million.0 atm)*( 4 grams/mol)/(0.0821 L*atm/mol*ok)(298 ok) = 0.163 grams/Liter d(Ne) = (one million.0 atm)*(20.18 grams/mol)/(0.0821 L*atm/mol*ok)(298 ok) = 0.824 grams/Liter because of the fact the air has a density of 0.00117 g/ml (observe mL, not Liters), CO, He, and Ne will drift in this air because of the fact their densities are decrease than that of the air.
2016-11-23 17:27:52 · answer #3 · answered by Anonymous · 0⤊ 0⤋