In this question: In a titration experiment 50 mL of a 0.1 M HCl solution neutralized a 0.2M Al(OH)3 solution - how many mL of the hydroxide solution were used, I am expected to figure out that I need 3 HCl, in order to make the formula:
Al(OH)3 + 3 HCl How do I know I need 3 HCl?
Thanks!
2007-03-26 09:36:21 · 3 answers · asked by LearnChem 1 in Science & Mathematics ➔ Chemistry
You should know that you are going to have 1HCl reacting with every OH molecule. so the net ionic equation will be OH + H --> H2O and sense there is 3 molecules of OH will dissociate from Al(OH)3 you will need have 3 molecules of HCl to neutralize the Al(OH)3
2007-03-26 09:58:05 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The balanced equation is:
Al(OH)3 + 3 HCl ---> 3 AlCl3 + 3 H2O
50 x 0.1M HCl = 5mm HCl
Therefore 5/3 mm Al(OH)3
0.2M x V = 1.67mm
V = 8.35mL
2007-03-26 16:49:13 · answer #2 · answered by Jabberwock 5 · 0⤊ 0⤋
You need 3 HCl because the formula of the salt you are making is AlCl3!
2007-03-26 16:45:30 · answer #3 · answered by Gervald F 7 · 0⤊ 0⤋