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If a lightbulb were to emit negative light would it be visible? Would it be the negative of visible(or anti-visible, or totally imperceptible)?

By negative light I mean a theoretical opposite to light, not just darkness as it is the absence of light. So regular light is +, darkness is 0, negative light would be -

2007-03-26 04:04:32 · 3 answers · asked by Luis 6 in Science & Mathematics Physics

To expand, there seems to be energy and negative energy, so what I'm looking for is to find out about negative light, which is a beam basically, so this would be an opposing beam whereby if it hits a beam of the same strength of the opposite side of the equation would create 0 light, they'd cancel eachother out.

I'm not sure if this helps.

2007-03-26 08:17:28 · update #1

3 answers

well... if it emits heat.. they I would have to say yes.. take a black hole.. it emits no light at all.. but does emit heat.. the black hole itself can not be seen.. but the event horizon can be seen... because of the heat... which is not from the black hole itself... but from things outside the black hole....

after thinking about it.. I would have to say... no it is not visible... light after all is enegry which is also heat... without the energy... you should not be able to see it

2007-03-26 04:10:57 · answer #1 · answered by Larry M 3 · 0 0

You really haven't well defined by what you mean as negative light. If you mean in the sense that anti-matter is "negative matter" then you'll be surprised to know that a photon is its own anti-particle. Therefore, negative light is normal light.

2007-03-26 04:18:04 · answer #2 · answered by Tim 4 · 0 0

Light is transmitted by photons, tiny packets of mass-less energy that travel at the speed of light. The photon is its own anti-particle. Therefore photons or anti-photons would shine as bright.

2007-03-26 05:42:44 · answer #3 · answered by Kes 7 · 0 0

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