A tank is filled with an ideal gas at 400 K and pressure of 1.00 atm.
2007-03-26 02:01:11 · 5 answers · asked by RhondaJo 2 in Science & Mathematics ➔ Physics
For constant volume
P1/T1 = P2/T2
1/400 = 2/T2
T2 = 800K
2007-03-26 02:04:42 · answer #1 · answered by Orinoco 7 · 2⤊ 0⤋
If the pressure doubles, so does the temperature. PV/T being constant for an ideal gas.
Steve
2007-03-26 02:05:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
the keyword is inflexible tank; this implies the quantity does no longer enhance and you realize the quantity continues to be an analogous; for this reason if the stress doubles with an analogous quantity the temperature doubles delta U = delta Q + delta W because of fact the quantity does no longer substitute, there is not any PV paintings, so the finished substitute in inner potential = warmth pass; the substitute in inner potential is with reference to the temp substitute, so discover delta U and you have delta Q
2016-12-19 14:07:12 · answer #3 · answered by ? 3 · 0⤊ 0⤋
Use the ideal gas equation.
PV/T = constant
Here V is also a constant
P/T = Constant
P1/T1 = P2/T2
Using P2 = 2P1 this gives
T2 = 2T1 = 800 K
2007-03-26 02:09:26 · answer #4 · answered by dudara 4 · 0⤊ 0⤋
If the Volume has stayed the same (I'll assume it has) then if the pressure has doubled, the temperature has doubled aswell.
i.e. 800 Kelvin
2007-03-26 02:05:18 · answer #5 · answered by Doctor Q 6 · 0⤊ 0⤋