a mixture of water that has 12 keV phtons.
Weight fractions of Hydrogen and Oxygen are 2/18 are 16/18 respectively.
thus the net aborption coefficient is
U = (0.045 * 2/18) + (0.283 *16/18)
I dont understand where 0.045 and 0.283 come from? Help please!
2007-03-26 01:31:25 · 2 answers · asked by sunny 4 in Science & Mathematics ➔ Physics
please if it is possible for you, if you could show me how to get from 12keV into 0.045 (m2 /kg) that would be much appreciated
2007-03-26 01:42:49 · update #1
They are the absorption coefficients for pure hydrogen and oxygen alone respectively.
2007-03-26 01:36:15 · answer #1 · answered by Taharqa 3 · 0⤊ 0⤋
I suspect that you aren't supposed to derive the attenuation coefficients of Hydrogen and Oxygen. They're probably in a table in your book somewhere. I think you're just being asked to calculate the overall coefficient using the given coefficients and the weight fractions.
2007-03-26 01:37:27 · answer #2 · answered by Anonymous · 0⤊ 0⤋