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Sr(NO3)2 (aq) is added to 1.0 L of solution containing 0.020 mol F- and 0.10 mol SO4(2-) at constant volume. Which salt precipitates first? What is [Sr2+] in solution when the precipitate start to form?

Ksp for SrSO4 = 7.6 x 10^-7
Ksp for SrF2 = 7.9 x 10^-10

2007-03-26 00:44:59 · 1 answers · asked by sky_blue 1 in Science & Mathematics Chemistry

1 answers

For the first case: [Sr+2] = Ksp/(F-)^2 = 1.98 x 10^-6

For the second case: [Sr+2] = Ksp/(SO4-2) = 7.6 x 10^-6

SrSO4 will precipitate first at a strontium ion concentration of
7.6 x 10^-6 molar. This is about 4 x more concentrated than when SrF2 will begin to precipitate.

2007-03-26 01:55:46 · answer #1 · answered by docrider28 4 · 0 0

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