How many two-digit whole numbers yield a remainder of 1 when divided by 5 and also yield a remainder of of one when divided by 7?
2007-03-26 00:04:48 · 4 answers · asked by Judo 1 in Science & Mathematics ➔ Mathematics
Two:
36 (1 x 7x5 + 1)
71 (2 x 7x5 + 1)
2007-03-26 00:08:22 · answer #1 · answered by novangelis 7 · 0⤊ 0⤋
7x5=35 add 1 for 36
7x10=70 add 1 for 71
5x7=35 add 1 for 36
5x14=70 add 1 for 71
ergo, 2 two-digit whole numbers can be divided by 5 or 7 with a remainder of 1; 36 and 71
2007-03-26 07:18:08 · answer #2 · answered by Peter H 2 · 0⤊ 0⤋
All the numbers that conform to: 5*7*n + 1 or
35n + 1
For n=3, 35n + 1 > 99, so....
answer is 2 (36 and 71)
2007-03-26 07:10:26 · answer #3 · answered by blighmaster 3 · 0⤊ 0⤋
eehhh....36
36/5 = 7 remain 1
36/7 = 5 remain 1
2007-03-26 07:11:02 · answer #4 · answered by mazesaw 1 · 0⤊ 0⤋