This is a retype of my previous question:
1/(x+2) - 1/(x-2)= 1
so the question still remains the same : can any of you Einsteins help me identify that bloody x....as I seem to stupid to do so....thanks a lot folks
2007-03-24 22:05:23 · 10 answers · asked by Nina 2 in Science & Mathematics ➔ Mathematics
multiply both sides by (x-2)(x+2)
(x-2) - (x + 2) = (x-2)(x+2)
-4 = x^2 -4
x^2 = 0
x=0
2007-03-24 22:09:10 · answer #1 · answered by yup5 2 · 2⤊ 0⤋
Multiply each side of the equation by the
Lowest Common Denominator ( x + 2 )( x - 2 ) .
The result ( x - 2 ) - ( x + 2 ) = ( x + 2 )( x - 2 )
reduces to -4 = x² - 4 and x = 0 .
2007-03-25 06:14:25 · answer #2 · answered by Zax 3 · 0⤊ 0⤋
So, first u need to make them a common denominater
(x+2)(x-2).
So, u get (x-2)/(x+2)(x-2)-(x+2)/(x+2)(x-2).
So, combine numeraters
x-2-(x+2), x-2-x-2, -4.
-4/(x+2)(x-2)=1.
So, now just cross multiply and u get (x+2)(x-2)=-4.
So, x^2-4=-4,
x^2=0
x=0
To Check:
Substitute x=1 into the equation.
To skip a couple of steps.
1/2--1/2=1
1/2+1/2=1
1=1
Hope this Helps!!!
2007-03-25 09:14:22 · answer #3 · answered by quickster94 3 · 0⤊ 0⤋
X both sides by (x + 2).(x - 2):-
(x - 2) - (x + 2) = (x + 2).(x - 2)
- 4 = x² - 4
x² = 0
x = 0
Check for x = 0:-
LHS = 1/2 - 1/(-2) = 1/2 + 1/2 = 1
RHS = 1
LHS = RHS
So answer IS x = 0 from given information!
2007-03-25 05:32:17 · answer #4 · answered by Como 7 · 0⤊ 0⤋
the answers 0....
take lcm of the LHS
[(x-2)-(x+2)]/(x^2 - 4)=1
[x-2-x-2]/(x^2 - 4)=1
x and -x cancel out each other and we get
(-2-2)/(x^2 - 4)=1
-4/(x^2 - 4)=1
-4=(x^2 - 4)
-4+4 = x^2
x^2=0
this implies that x=0
2007-03-25 05:36:35 · answer #5 · answered by devilishly_snappish 1 · 0⤊ 0⤋
i think you have to get the same common denominator so you times 1/(x+2) by (x-2) to get the same denominator of (x+2)(x-2) so you'd get 1(x-2)/(x+2)(x-2) for the first bit.
next you have to times 1/(x-2) by (x+2) so that the denominator for that one can become (x+2)(x-2):
the equasion now is -
1(x-2)/(x+2)(x-2) - 1(x+2)/(x+2)(x-2) = 1
the denominators cancel out so you're just left with the top-
1(x-2) - 1(x+2) = 1
which is justt x - 2 - x +2 = 1
it cancels out to =1
:S i think :P lololololol
2007-03-25 05:16:14 · answer #6 · answered by homestar_cutie_runner 1 · 0⤊ 0⤋
1/x+2-1/x-2=1
x-2-(x+2)/x*-4=1 (*=2, ok I still do not how to write the power!)
x-2-x-2/x*-4=1
-4/x*-4=1
x*-4=-4
x*=0
x=0
2007-03-25 05:51:37 · answer #7 · answered by ? 5 · 0⤊ 0⤋
The answer is 0.
2007-03-25 05:13:42 · answer #8 · answered by Failure 2 · 0⤊ 0⤋
1/(x+2)-1/(x-2)=1
L.C.M
x-2-(x+2)/(x+2)(x-2)=1
now that becomes
-4/x2(square)-4=1/1
cross multiply
now
-4=x2(square)-4
-4 is cancelled
therefore
x2(square)=0
and x=0
ur answer is X=0
2007-03-25 05:20:12 · answer #9 · answered by Anmol 2 · 0⤊ 0⤋
you do know that the x can stand for anything in maths don't you?
2007-03-25 05:11:58 · answer #10 · answered by Andrew H 1 · 0⤊ 1⤋