Middle term splitting?

Question

I got this home work about splitting the middle term and factorization of a lenear equation in 1 variable. i dont understand it. please help.

Answer 1

ok first of all i will give my own eqation for this

x2(square)-12x+11

now first multiply the last term by the first term
and get the factors of the last term.

and get two no. which by adding or subtracting will give the middle term and by mulyplying will give the last product of first and last term

Now for my equation
i.e.
x2(square)-12x+
(i)11*x2(square)=11x2(square)
(ii)factors of 11 are (11*1)
(iii)-11x-1x=12x
(iv)-11*-1=11

therefore the answer will be(x-11)(x-1)
and x will be 11 or 1

Answer 2

you have 2 strategies to try this yet whilst the coefficient of y is a huge extensive style consisting of 35 purely one way works first of all you multiply the extensive style infront of the y^2 (this is +35) with the final extensive style (this is -12) and you detect -420. now you should discover 2 numbers that as quickly as superior they supply you -420 and whilst further +13 (the middle extensive style) those numbers are:+28 and -15 so which you chop up the middle term which became +13y to +28y-15y 35y^2+28y-15y-12 and then factorise: 7y(5y+4)-3(5y+4) once you are trying this you will continually discover that the two brackets are the comparable and this will become: (7y-3)(5y+4)it is the suitable answer wish this has helped:):)