how to solve the following equation for y:?

Question

hi,

i would like to find out how to solve this problem

i would like to find out how to solve the following equation for y.

log3(14 y-15) = 3 x^3+2 (the 3 in the first part means the base 3)

thanks for your help.




thanks for your help.

Answer 1

14y - 15 = 3^(3 x^3+2)

14y = 3^(3 x^3+2) + 15
y = (3^(3 x^3+2) + 15)/ 14

Answer 2

3(14 y-15) = 3 x^3+2

first you distribute on the left side of the equation

you multiply 3 by everything inside the parentheses so it turns to..


42y - 45 = 3x^3 + 2

next, get rid of the 45 by adding it to both sides

42y= 3x^3 + 47

Answer 3

14y - 15 = 3^(3x³ + 2)
14y = 15 + 3^(3x³ + 2)
y = (1/14).[15 + 3^(3x³ + 2) ]
y = (1/14).[15 + 9.(3^(3x³) ]

Answer 4

Everyhing above is OK, but something is missing. That's
14y-15>0,
14y>15
y>15/14
because this is the prerequisite for the log to be OK.