a square is a 2D figure or an integer multiplied by itself...you can only turn a 2D figure upside down if you define a top and therefore define a bottom. Other wise the top/bottom are at the viewer discretion
2007-03-24 22:48:57
·
answer #1
·
answered by albwa2smart 2
·
0⤊
1⤋
A square cannot be upside-down unless it has some factor that defines one direction or side as the "top".
2007-03-24 20:35:17
·
answer #2
·
answered by Love Answers 2
·
1⤊
0⤋
You can't because there is no "upside down" for a square. A square, by definition, is the same when it is standing on all four sides.
2007-03-24 22:40:22
·
answer #3
·
answered by the_emrod 7
·
0⤊
1⤋
you can't tell if it is up side down there is no good answer for that question, you can't even tell if it is right side up you could even go to wikipedia and find out, It won't give you a good answer. unless it has some factor that defines one direction or side as the "top". so that is all i've got so sorry an good luck with that problem.
2007-04-01 16:49:00
·
answer #4
·
answered by Edweirdo D 1
·
0⤊
0⤋
it does not matter if a square is upside down because all 4 sides of a square are equal,,so anyhow whichever side u see,,it willl appear the same!!!
2007-03-24 20:37:42
·
answer #5
·
answered by kitkat 3
·
0⤊
2⤋
would depend on weither or not it is a geometric or integer square. 10 to the 2nd would be 100 but 10 to the -2nd would -100, as for geometric forms only know the orientation of the object would allow for an assumption as to it's top or bottom.
2007-03-24 21:42:08
·
answer #6
·
answered by Hecaeta 3
·
0⤊
1⤋
as far as i'm concerned, all squares are upside down. and right side up, for that matter.
2007-03-24 20:39:24
·
answer #7
·
answered by tlic 1
·
0⤊
2⤋
you cant why would you want to know if it was upside down anyways?
2007-03-29 11:57:32
·
answer #8
·
answered by .::$*Mrs.Smith*$::. 2
·
0⤊
0⤋
He's standing on his head. Zing
2007-03-24 20:36:12
·
answer #9
·
answered by Anonymous
·
0⤊
2⤋
It will tell you.
2007-03-29 01:46:39
·
answer #10
·
answered by Randy K 1
·
0⤊
0⤋