How many mL of 2.0 molar HCl are required to dissolve 0.350 g of FeS?
(FeS + 2HCl ---> FeCl2 +H2S)
2007-03-24 19:54:05 · 6 answers · asked by hiscageofstars 1 in Science & Mathematics ➔ Chemistry
Molar mass of FeS = 56+32 = 88 g
So, moles of FeS = 0.35/88 = 3.97 x 10^-3
Moles of HCl = 2 x 3.97 x 10^-3
So, mL reqd. = 3.97 x 10^-3 L = 3.97 mL
2007-03-24 20:09:59 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋
2
2007-03-24 19:57:25 · answer #2 · answered by ajaz a 1 · 0⤊ 0⤋
0.0079617834 mol HCl or
0.2902866 g
2007-03-24 20:02:49 · answer #3 · answered by Lisa L 2 · 0⤊ 0⤋
36.46 g/mol hcl / water @37% 100/37 = 2.702
*36.46=98.540 g. of 37%hcl
2007-03-24 20:19:14 · answer #4 · answered by David M 1 · 0⤊ 0⤋
3.98 mL
2007-03-24 20:26:29 · answer #5 · answered by RVV 1 · 0⤊ 0⤋
3.97mL
2007-03-24 20:11:40 · answer #6 · answered by kartik 2 · 0⤊ 0⤋