g(t+5)=[(t+5)+4]/3=-7
Therefore, t+9=-21 and t=-30.
2007-03-24 18:34:39
·
answer #1
·
answered by bruinfan 7
·
0⤊
0⤋
I don't see any use for the function f(x), so I'm going to guess that we're trying to answer part of a longer problem.
If g(n) = (n+4)/3, then substitute t+5 for n:
g(t+5) = [(t+5) +4]/3 = -7;
t+5+4 = -7*3
t+9= -21
t = -30
Check: g(t+5) = g(-25) = (-25+4)/3 = -21/3 = -7.
Good luck, work hard, and stay away from drugs.
2007-03-25 01:38:31
·
answer #2
·
answered by MikeyZ 3
·
0⤊
0⤋
g(t+5) = ((t+5) + 4)/3 = (t+9)/3 from the definition of g(n)
But g(t+5) = -7
So (t+9)/3 = -7. Therefore t+9 = -21 so t = -30.
The fact that f(x) = 3x - 4 is irrelevant to finding t.
2007-03-25 01:35:05
·
answer #3
·
answered by Bazz 4
·
0⤊
0⤋
g(n) = (n+4)/3
thus, g(t+5) = ((t+5)+4)/3 = (t+9)/3=-7
=> t+9 = 3*(-7)=-21
=> t = -21-9 = -30
2007-03-25 01:41:13
·
answer #4
·
answered by Thor 1
·
0⤊
0⤋
Well, um you don't even need the first f(x) part.
Okay: so:
g(t+5) = ((t+5)+4)/3 = 8
t+9 = 24
t = 15
whoops, sorry. This is wrong because I thought you wrote 7 instead of -7.
2007-03-25 01:33:24
·
answer #5
·
answered by Bob R. 6
·
0⤊
0⤋
If g(n) = (n + 4)/3, g(t + 5) = ((t + 5) + 4)/3
So, g(t + 5) = (t + 9)/3
If g(t + 5) = -7
(t + 9)/3 = -7
t + 9 = -21
t = -30
2007-03-25 01:35:00
·
answer #6
·
answered by polymac98 2
·
0⤊
0⤋
plug t+5 into n
g(t+5) = [(t+5)+4]/3 = -7
(t+9)= -21
t = -30
2007-03-25 01:36:49
·
answer #7
·
answered by HayatoK 2
·
0⤊
0⤋