Select all that apply and tell me how you did it!! Thanks
(a) Na+ and Ba2+
carbonate
iodide
nitrate
strong acid
strong base
sulfate
sulfide
(b) K+ and Pb2+
carbonate
iodide
nitrate
strong acid
strong base
sulfate
sulfide
(c) Zn2+ and Hg2+
carbonate
iodide
nitrate
strong acid
strong base
sulfate
sulfide
2007-03-24 14:39:05 · 4 answers · asked by Hadeer S 1 in Science & Mathematics ➔ Chemistry
This is homework that I don't understand. If you can nudge me in the right direction, that would be great.
2007-03-24 14:47:17 · update #1
(a) I would use sulfate or carbonate. The barium sulfate is less soluble than the carbonate. Barium sulfide apparently hydrolyses water so im not sure what it would do exactly.
(b) Carbonate, iodide, strong base, sulfate and sulfide will form a precipitate with the lead. The strong base will cause a precipitate because a strong base would have many hydroxide ions and lead hydroxide ( Pb(OH)2 ) is insoluble.
(c) Both ions will both precipitate with many of them. Zinc iodide is soluble while mercury (II) iodide isnt. Zinc sulfate is soluble while mercury (II) sulfate isnt. So iodide and sulfate would be used to differentiate.
With all the above, once a precipiate has formed you can decant off the liquid and seperate the ions that way.
2007-03-24 15:05:20 · answer #1 · answered by neotaco 2 · 3⤊ 0⤋
1) sulfate. BaSO4 is insoluble, Na2SO4 is soluble
2) iodide. PbI2 is insoluble, KI is soluble
3) sulfate. HgSO4 is insoluble, ZnSO4 is soluble
2007-03-24 16:20:20 · answer #2 · answered by TheOnlyBeldin 7 · 1⤊ 0⤋
a) Sulfate; b) Sulfide; c) sulfide
2007-03-24 14:55:58 · answer #3 · answered by Bright A 1 · 1⤊ 0⤋
Is this a homework we should answer??
2007-03-24 14:45:09 · answer #4 · answered by chem_star 2 · 0⤊ 2⤋