A snail is at the bottom of a 6-foot well and wants to climb to the top. The snail can climb 3 feet while the sun is up, but slides down 1 foot at night while sleeping. The snail has a fatigue factor of 10%, which means that on each successive day the snail climbs 10% 3 = 0.3 feet less than it did the previous day. (The distance lost to fatigue is always 10% of the first day's climbing distance.) On what day does the snail leave the well, i.e., what is the first day during which the snail's height exceeds 6 feet? (A day consists of a period of sunlight followed by a period of darkness.)
2007-03-24 09:55:12 · 4 answers · asked by mreed72 3 in Education & Reference ➔ Trivia
do your own homework and get a calculator!
2007-03-24 10:02:08 · answer #1 · answered by Allison 2 · 1⤊ 2⤋
i believe that it would be about 3.75 days. since the fatigue factor codominates the sunlight (264.3867) fatigue losses the rate of the climbing by .2375 times every 47 seconds. therefore by the 3rd day the fatigue would increase causin the .75 days it takes about 12 minutes for a sail to travel 5 inches and the fatigue have increased so that would be lowered by .6728 the sunlight would increase the fatigue and cause the temperture of the blood to go up also causing the snail to decrease the rate of moving. by 4:00 am the snauil would have reached the top with a fatigue of about 8.215 and the sun would be at a 36.98 degree angle
2007-03-24 10:15:38 · answer #2 · answered by ms.problemsolver 3 · 1⤊ 1⤋
Now I'm getting a headache.
Thanks a lot!
2007-03-24 14:44:55 · answer #3 · answered by pat z 7 · 1⤊ 1⤋
OOOWWW!! my brain... errrrr 11 days after it fell in or maybe10... how did it fall in anyway?
2007-03-24 10:22:09 · answer #4 · answered by Anonymous · 1⤊ 1⤋