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specific heat of ice: 2.10 J/(g deg C)
specific heat if water: 4.18 J/(g deg C)
heat of fusion: 333 J/g
heat of vaporization: 2258 J/g

2007-03-24 06:52:11 · 3 answers · asked by Kayla H 1 in Science & Mathematics Chemistry

3 answers

Q = 64(333 + 75*4.18)
Q = 64(333 + 313.5)
Q = 64(646.5)
Q = 41,376 J

2007-03-24 07:13:16 · answer #1 · answered by Helmut 7 · 0 0

first melt the ice
Q1 = m*heat of fusion =64*333=21312 j
Q2 =heat the water to 75°

Q2 =mc (tf -ti) = 64*4.18*75 =20064J

Q = Q1+Q2 =41376 J

2007-03-24 14:00:41 · answer #2 · answered by maussy 7 · 0 0

first u walk to the bathroom then u pull down ur pants or shorts or watever then u pull down ur underwear then u sit then u pee

thats how u go to the bathroom

2007-03-24 14:25:58 · answer #3 · answered by idaloo2002 2 · 0 0

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