English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2007-03-24 02:04:43 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

4 answers

19.2 x 79.5/63.5

2007-03-24 02:11:38 · answer #1 · answered by Gervald F 7 · 0 0

2 CuO -> 2 Cu + O2

2 moles of copper oxide would react to form 2 moles of copper.


1 mole of CuO =

1 x Cu = 1 x 63.5 = 63.5g
1 x O =1 x 16 = 16g

1 mole = 79.5g 2 moles = 159 g

1 mole of copper = 1 x 63.5
2 moles = 127g


Therefore:

159g of CuO reacts to give 127g of copper

159g / 127g -> (127 / 127) = 1 g of copper

(159 / 127) x 19.2 -> 19.2g of copper


24.0g -> 19.2g

24.0g copper oxide would give 19.2g copper

=]

2007-03-24 02:22:39 · answer #2 · answered by Maureen 3 · 0 0

2CuO---------> 2Cu + O2
That is the balanced equation for the thermal decomposition of CuO.

the Mole ratio of CuO:Cu is 1:1

The RAM of Cu is 29g

1mole =64g
? = 19.2g

19.2/64=0.3moles

Grams of CuO required:
0.3*(64+16)
=24g

2007-03-24 02:19:00 · answer #3 · answered by zoe g 1 · 0 0

2CuO---->2Cu + O2

mol.wt of CuOin eq.=159
mol wt of Cu in eq.=127

acc. to the eq.
159 gm of CuO produces 127 gm of Cu
x gm of CuO will produce 19.2 gm of Cu.

159------127
x---------19.2

(159 x 19.2)/127=24.03

ANS: 24.03 gm of CuO.

2007-03-24 02:33:42 · answer #4 · answered by question??? 1 · 0 0

fedest.com, questions and answers