Grade 11 Chemistry...?

Question

The equation from the combustion of hexane is:
C6H14(g)+19/2 O2(g) -(arrow sign) 6CO2(g)+7H2O(g)

Calculate the number of moles of
a) CO2 produced in the combustion of 1.50 moles of hexane

b) H2O produced in te combustion of 0.25 moles of hexane

c) O2 consumed in the combustion of 0.40 moles of hexane

Note: (g) is a subscript and means gas. I don't know the processes involved in finding the answers. Could you please, chemistry whizzes, show me and explain to me the processes before showing the answer. I have been looking through my books etc for over 1 hr 20 minutes (honestly) on these 3 parts to the question. Please help me! Thankyou

Answer 1

(a) 1mole of hexane will produce 6 moles of carbon dioxide, therefore 1.5 moles of hexane will produce (6 *1.5=) 9 moles of carbon dioxide.

(b) 1 mole of hexane will produce 7 moles of water, therefore 0.25 moles of hexane will produce (0.25*7)= 1.75 moles of water.

(c) One mole of hexane will react with 9.5 moles of oxygen, therefore 0.4 moles of oxygen will react with (0.4*9.5)= 3.8 moles of oxygen.

These figures are obtained from the balanced equation.

Answer 2

Alright, this is very easy. You just need to take a deep breath and go calmly with it. I used to hate these questions too.

a) The equation given to you is already a balanced one. To work this out, you just need arithmetic knowledge.

For first question:

You need to find out the number of moles of CO2 produced from combustion of 1.5 moles of hexane, C6H14.

Check your equation given to you.
You will see in it that:

1 mole of C6H14 produces 6 moles of CO2.
Hence, 1.5 moles of C6H14 will produce {(6/1) x 1.5}
= 9 moles of CO2.

b) same principle.

1 mole of C6H14 produces 7 moles of H2O
Hence, 0.25 moles of C6H14 will produce { (7/1) x 0.25}
=1.75 moles of H2O

c) Same principle again.

1 mole of C6H14 requires 19.5moles of O2
Hence, 0.40 moles will require {(19.5/1) x 0.40}
= 7.8 moles of O2

Hope this helps : )

Answer 3

I have taken Chemistry before and hated it . I had to take it again in college and it still stunk however there are websites that may help you. If yoou can do it now you can breeze through college Chem.

this website may help you
http://dbhs.wvusd.k12.ca.us/webdocs/Mole/Grams-to-Moles.html
If not google the question

Just plug in what you need.

Answer 4

tip: use ratios. u always need to have the same ratios of moles between reactants and products
e.g. for the reaction 2HCl + Zn --> ZnCl2 + H2

for every mole of HCl used, half mole of ZnCl and H2 is produced - the ratio is 2:1

try to apply that to your equation
hope it helps

Answer 5

http://www.amazon.com/s/ref=nb_ss_gw/102-8295639-8848965?url=search-alias%3Daps&field-keywords=schaums+chemistry