2007-03-24 01:04:21 · 12 answers · asked by Shahnrsf 1 in Science & Mathematics ➔ Mathematics
subtract 11x from both sides
2x -1 -11x > 9 combine
-9x -1 > 9 add 1 to both
-9x -1+1 > 9 +1
-9x > 10 divide by -9 but REMEMBER
WHEN YOU DIVIDE BY NEGATIVE YOU REVERSE INEQUALITY
-9x / -9 < 10/ -9
x < -10/9
that is solution i hope that helpppps
2007-03-24 01:09:31 · answer #1 · answered by emy 3 · 1⤊ 0⤋
2x – 1 > 11x + 9
-1-9 > 11x-2x
-10 > 9x
-10/9 >x
So x < -10/9
2007-03-24 09:45:27 · answer #2 · answered by lazyboii 2 · 1⤊ 0⤋
2x-1>11x+9
= 0>(11x-2x)+(9+1)
= -10>9x
= x< -10/9
2007-03-24 08:10:40 · answer #3 · answered by R.V.Aswath narayanan 1 · 1⤊ 0⤋
2x-1>11x+9
2x-11x>9+1
-9x>10
x< -10/9
the change from>to < is as a result of the movement of the - sign to the other side
2007-03-24 08:16:12 · answer #4 · answered by omo 2 · 1⤊ 0⤋
2x - 1 > 11x + 9
2x - 1 - 2x > 11x + 9 - 2x
- 1 > 9x + 9
- 1 - 9 > 9x + 9 - 9
- 10 > 9x
- 10 / 9 > 9x / 9
- 10 / 9 > x
- 1 1/9 > x
- - - - - - - - - - - -s-
2007-03-24 10:51:43 · answer #5 · answered by SAMUEL D 7 · 0⤊ 0⤋
2x-1>11x+9
2x-11x>9+1
-9x>10, divided by (-1)
9x>-10
x>-10/9
x>-1 1/9
2007-03-24 09:25:58 · answer #6 · answered by nisa 1 · 1⤊ 0⤋
-10/9>x
2007-03-24 08:08:16 · answer #7 · answered by spyderman1212 4 · 1⤊ 1⤋
11x-2x<-1-9
9x<-10
x<-10/9
2007-03-24 08:09:14 · answer #8 · answered by Anonymous · 0⤊ 1⤋
- 1 > 9x + 9
9x < - 10
x < - (10/9)
2007-03-24 10:00:30 · answer #9 · answered by Como 7 · 1⤊ 0⤋
-9x>10
9x<-10
x<-10/9
First you transpose. Signs change after transposing. The greater/lesser than sign changes if the side with the x is negative. Ya know what happens next.
2007-03-24 08:46:26 · answer #10 · answered by ♫tweet75♫ 3 · 1⤊ 0⤋