2007-03-24 00:17:02 · 8 answers · asked by scorpiangrl055 1 in Science & Mathematics ➔ Mathematics
5x² - 17/2 + 3/2 = 0
2(5x²) - 2(17/2x) + 2(3/2) = 2(0)
10x² - 17x + 3 = 0
Find the sum of the middle term
Multiply the first term 10 times the last term 3 equals 30 and factor
Factors of 30 = 1 2 3 5 6 10 15 30
- 2 and - 15 satisfy the sum of the middle term
insert - 2x and - 15x into the equation
10x² - 17x + 3 = 0
10x² - 2x - 15x + 3 = 0
2x(5x - 1) - 3 (5x - 1)
(2x - 3)(5x - 1)
- - - - - - - - - -s-
2007-03-24 02:19:19 · answer #1 · answered by SAMUEL D 7 · 1⤊ 0⤋
Yoou gotta learn more, my friend.
In order to factorise this polynomial, you'd do better to take out a common multiple of 1/2 to avoid all the tedious efforts i know u have been doing.
So,
5x^2 - 17/2x + 3/2
= 1/2{10x^2 - 17x + 3}
= 1/2{10x^2 - 15x - 2x + 3}
= 1/2{5x(2x - 3) - 1(2x - 3)}
= 1/2(5x - 1)(2x - 3)
Its as simple as that!
If you still don't want 1/2 as a coefficient, you can just multiply one of the factors by 1/2 and kick off the '1/2' coefficient!
2007-03-24 09:39:22 · answer #2 · answered by Naval Architect 5 · 1⤊ 0⤋
first take 1/2 as common factor from all terms to avoid existance of fractions:
1/2 ( 10x^2 - 17x + 3 )
1/2 ( 5x - 1) (2x - 3 )
now check for middle term -2x + -15x = -17x great
you may mutliply 1/2 into either of the tow brackets again and you may not
( 5/2x - 1/2 ) ( 2x -3 )
or
( 5x - 1 )(1x -3/2 )
hope that helps
2007-03-24 07:54:12 · answer #3 · answered by emy 3 · 1⤊ 0⤋
5X^2-17X/2 +3/2 = 0
( multiply this equation by 2)
10X^2-17X+3=0
(5x-1)(2x-3) = 0
5x-1 =0
5x =1
x = 1/5
or
2x-3=0
2x=3
x =2/3
2007-03-24 09:49:12 · answer #4 · answered by lazyboii 2 · 1⤊ 0⤋
5x^2-17/2x+3/2
(5x-1)(x-3/2)
Check:
5x^2-15/2x-1x+3/2=
5x^2-15/2x-2/2x+3/2=
5x^2-17/2x+3/2
or this
Multiply the whole thing by 2:
10x^2-17x+3
(2x-3)(5x-1)
2007-03-24 10:35:26 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(5/2x-1/2)(2x-3)
(again with the "factorise"?!)
=)
2007-03-24 07:27:23 · answer #6 · answered by Popo B 3 · 3⤊ 1⤋
(2x-3)(5x-1)=0
2007-03-24 07:29:11 · answer #7 · answered by Anonymous · 1⤊ 1⤋
(5x-1)(2x-3)
Please give me best answer thanks!
2007-03-24 08:33:12 · answer #8 · answered by Anonymous · 1⤊ 0⤋