a vertical pole has 2/5ths of its length in water and 3/20ths in mud.if 15 metres is out of the water what is the length of the pole?
2007-03-23 23:02:42 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
in mud 8/20
in water 3/20
above water 11/20 = 15 m
length = 15*20/11 = 27 3/11 m
2007-03-23 23:06:37 · answer #1 · answered by hustolemyname 6 · 0⤊ 1⤋
First chose the same denominator for fractions
2 /5 =8/20
so 8/20+3/20 = 11/20 are under liquid and 20/20-11/20=9/20out of liquid
(9/20)p = 15 or 9p/20 = 15 and p = 300/9 =33.33m
2007-03-24 06:27:54 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
first, convert the fractions to common terms
2/5 = .40
3/20=.15
So, .45 of the pole is exposed (you said 'out of the water' in your question)
.45x=15
divide by .45
x=33.333 meters
2007-03-24 06:09:12 · answer #3 · answered by Matthew P 4 · 0⤊ 0⤋
37.5 meters
Please give me best answer thanks!
2007-03-24 09:11:43 · answer #4 · answered by Anonymous · 0⤊ 0⤋