Can any 1 answer this please and show the working out so i can figure out how u got the answer.?

Question

the percentage of sugar in a solution of sugar and water is 9 %.if 4 litres of this solution has 500 mL of water added to it , what is the percentage of sugar in the new solution

Answer 1

% of sugar in 4L = 9%
Volume of sugar = 9*4/100 = 36/100
if 1/2 L of water is added
new volume = 4.5 litre
new % of sugar is = volume of sugar/total volume
= (36/100)/4.5 = 36/450 = 4/50 = 8/100

So answer is 8%

Answer 2

9% = 9 g per 100 mL.
Multiplying both by 40 brings it to 360 g / 4000 mL.
When you add 500 mL of water,
you will have 360 g / 4500 mL.
Now divide both by 45 to get (360 / 45) g / 100 mL.
360 / 45 = 8, that is, 8 g / 100 mL = 8%.

Answer 3

two ways (1L = 1000g)

1) the amount of sugar in 4L of 9% is 4*(9/100)*1000 =360g
after the addition of 500ml , the total volume is 4.5L . So , you have 360 g in 4.5 L = 360/4.5 = 80g/L
The solution is 8%

2) you have a solution of 9% in 4 L. after additon of 500mL=0.5L total volume is 4.5L

so new concentration 9*4/4.5 = 8%