i know x^2(x+2) is x^3+2x^2 but i don't know if it holds true for x+2(x^2) as the x+2 isn't in brackets.
thanks heaps!
2007-03-23 21:26:16 · 8 answers · asked by Jae 1 in Science & Mathematics ➔ Mathematics
it's false because if we look at x+2 (x^2), according to the orders of operation, it is actually x+( 2(x^2) ). one simple way of checking if the two functions are the same, pick several random numbers for x. For example, I pick x=3 and substitute in both equations and see what you get. If for several numbers, you get the same answer for the function, then it should be equivalent.
1) x+2 (x^2) = (3) + 2((3)^2) = 3 + 2(9) = 3 +18 = 21
2) x^3 + 2x^2 = (3)^3 + 2(3)^2 = 27 + 2(9) = 27 +18 = 45
as we can see (1) does not equal (2) so the expressions are inequivalent.
2007-03-23 21:37:10 · answer #1 · answered by Carmen L 2 · 1⤊ 0⤋
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2016-10-01 10:09:15 · answer #2 · answered by ? 4 · 0⤊ 0⤋
x+2 (x^2) = x^3+2x^2 FALSE
x+2 (x^2) = 2x^2 + x
2007-03-23 21:30:30 · answer #3 · answered by John S 6 · 0⤊ 0⤋
without the brackets around x+2, x+2(x^2)=2x^2+x so it is false. (with the exception of a few values of x where it might equal - by chance - i.e. x=1 and x=-1)
2007-03-23 21:30:51 · answer #4 · answered by misiekram 3 · 1⤊ 0⤋
See this compare
(a + b)c = ac + bc
(x+2)(x^2) = (x^3)+2x^2
c(a + b) = ca + cb
(x^2)(x+2) = (x^3)+2x^2
a + bc = a +bc
x+2(x^2) = x+2(x^2)
2007-03-23 21:41:31 · answer #5 · answered by PaeKm 3 · 0⤊ 0⤋
Unless you forgot some parenthesis, the answer is simply
X+2X^2
2007-03-23 21:32:01 · answer #6 · answered by Gary 2 · 0⤊ 0⤋
x+2(x^2)=x+2x^2
but
(x+2)x^2= x^3+2x^2
From the above it is clear that bracket decides
and hence x+2(x^2) is not same as x^2(x+2)
2007-03-23 22:10:29 · answer #7 · answered by RAJASEKHAR P 4 · 0⤊ 0⤋
it is false
righet answer is here
X+2(X^2)=X+2X^3
2007-03-23 21:36:42 · answer #8 · answered by amol 1 · 0⤊ 0⤋