English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I believe I did this problem right, but I would just like someone to confirm if it is right. Here is the question:

About how accurately should you measure the side of a square to be sure of calculating the area within 2% of it's original value?

A = S^2

dA = 2S dS

dA
(
dA
dA
2SdS
The S cancels with the S^2, so:

2dS
dS
Thus, I said the side of a square must be measured with a 1/100, or 1%, accuracy to be able to calculate the area within 2% of its original value.

2007-03-23 20:50:07 · 4 answers · asked by Ryan_1770 1 in Science & Mathematics Mathematics

4 answers

A = S^2 (1)
dA = 2S dS (2)
& dA
from (1) & (3) & simple mathematics calculation;
►dA
from (2)
2S dS
dS
►► dS

So you are right;

.

2007-03-23 21:26:31 · answer #1 · answered by arman.post 3 · 0 0

Yes its correct
S = x^2
S + dS = (x+dx)^2 = x^2 + 2xdx + (dx)^2
dS = 2xdx [ignoring (dx) ^2]
ds/S = 2 dx/x
but we know 2dx/x <= 0.02
dx/x <= 0.01
Answer is 1%

2007-03-24 04:07:06 · answer #2 · answered by Nishit V 3 · 0 0

from my view if u ask i think its correct bcoz the formula u r using is correct.

2007-03-24 03:58:48 · answer #3 · answered by mona 2 · 0 0

No!
Please give me best answer thanks!

2007-03-24 10:10:31 · answer #4 · answered by Anonymous · 0 0

fedest.com, questions and answers