4/15 x 30 x 1/2 = 4/15 * 15 = 4
6 1/2 divded by 3 =13/2 * 1/3 = 13/6 = 2 1/6
You got the second one right, but you got confused on the first one. it would be easier to take 1/2 of 30 first then you see it is 15. and so its 4/15 times 15 and the 15 cancels out and you are left with 4, have fun in prealgebra
2007-03-23 19:40:01
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answer #1
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answered by Anonymous
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4/15 x 30 x 1/2
4/15 x 15 ---> Start by multiplying 30 & 1/2 (or just dividing 30 by 2)
4 ---> Simplify (4/15 x 15 is the same as 4/15 x 15/1. The 15's can both reduce to 1, leaving you with 4.)
= 4
(6 1/2) / 3
(13/2) / 3 ---> Make 6 1/2 into improper fraction.
13/2 x 1/3 ---> Flip second fraction and multiply instead.
13/6 ---> Simplify.
2 1/6 ---> Reduce.
= 2 1/6
2007-03-24 02:45:19
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answer #2
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answered by Christina J ~ spygirl 2
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4/15 times 30 times 1/2 = 120/30 which would be 4.
6 1/2 divided by 3 is the same as multiplying 6 1/2 (13/2) by 1/3 so yes u do get 13/6 or 2 1/6.
2007-03-24 02:40:10
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answer #3
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answered by matt w 1
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Question 1
4/15 x 30 x 1/2 = 4 x 2 x 1/2 = 4 x 1 = 4
Question 2
6(1/2) / 3 = (13/2) / 3 = 13 / 6 = 2(1/6)
2007-03-24 03:56:06
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answer #4
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answered by Como 7
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4/15 x 30 x 1/2 = 4.
6 1/2 divided by 3 = 13/6 = 2 1/6.
2007-03-24 02:40:21
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answer #5
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answered by puppy.loveonFriday 1
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4/15 x 30/1 x 1/2 = 4
4/1 x 2/ 1 x 1/2
4/1 x 1/1 x 1/1
4
(6 1/2) / 3
13/2 x 1/3
13/6
2 1/ 6
2007-03-24 02:39:14
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answer #6
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answered by PenquinZ 1
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The first answer is wrong. you don't have to do anything special to the problem.. just line up the numarators and denomonators and times them out and then divide them out.... so, 4 time 30 time 1 = 120 (numarator) and then 15 times 2 = 30 (denomonator).... so, now you have 120/30, which equals 4. you did the bottom one right though... kudos to you... GOOD JOB!!! Hope it helps. Bye;O)
2007-03-24 02:39:49
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answer #7
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answered by buffman82me 2
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Your second one is right but I would go over the first one again :) Remember simplification rules [you can divide the numerator and denominator by common factors].
2007-03-24 02:41:02
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answer #8
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answered by TheMPower 2
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